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Each OFDM symbol contains, if 64-QAM is used, 6 bits per subcarrier (15kHz). There are, if normal CP is used, 7 OFDM symbols per slot. This ...

Calculate the maximum theoretical physical peak data rate in LTE radio interface

Each OFDM symbol contains, if 64-QAM is used, 6 bits per subcarrier (15kHz). There are, if normal CP is used, 7 OFDM symbols per slot. This ends up with 6*7 = 42 bits per slot.

One slot is 0.5 ms which gives us 42/0.5ms = 84kbps per sub-carrier.
If the full bandwidth, 20MHz, is used, there are
20MHz/15kHz=1333 sub-carriers.

However, only 1200 of these are used for user data. This
corresponds to 100 resource blocks.

1200*84kbps = 100,8 Mbps.
With four MIMO layers, we should be able to achieve 403,2 Mbps
of raw data rate in the physical layer.
What about the user data rate? The data rates used for L1/L2
signaling, reference signals, PBCH, SCH, layer 3 signaling and protocol headers has to be subtracted from this figure.

Then we end up with approximately 320 Mbps of user data rate on RLC level??
In UL we have approximately the same calculation, except that the gain from MIMO cannot be included, since no SU-MIMO is used in UL. Hence, approximately 80-100 Mbps of theoretical bitrate should be possible to reach.

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